Q. For angles of projection of a projectile at angles (45° − θ) and (45° + θ), the horizontal ranges described by the projectile are in the ratio of :
A) 1 : 1
B) 2 : 3
C) 1 : 2
D) 3 : 2
Explanation
[Solution from source] The range is R = u² sin 2θ/g. For (45° − θ), sin(90° − 2θ) = cos 2θ; for (45° + θ), sin(90° + 2θ) = cos 2θ. The two ranges are therefore equal, a ratio of 1 : 1, for any θ. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.