Q. 300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g = 10 m/s², work done against friction is :
A) 50 J
B) 100 J
C) zero
D) 150 J
Explanation
[Solution from source] Work against gravity is mgh = 2 × 10 × 10 = 200 J. The remaining 300 − 200 = 100 J of the work done is spent against friction (assuming no gain in kinetic energy). Zero would be true only on a frictionless incline. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.