When photons of energy hν fall on an aluminium plate (of work function E₀), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be :

Question

Dr. Abubacker · Accepted Answer

[Solution from source] Einstein's equation gives K = hν − E₀. At frequency 2ν, K' = 2hν − E₀ = (hν − E₀) + hν = K + hν. The kinetic energy does not simply double, because the work function is subtracted only once. Answer (4).

Q. When photons of energy hν fall on an aluminium plate (of work function E₀), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be :

Explanation

Reviewed by Dr. Abubacker

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