Two sound waves with wavelengths 5.0 m and 5.5 m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second :

Question

Dr. Abubacker · Accepted Answer

[Solution from source] The frequencies are 330/5.0 = 66 Hz and 330/5.5 = 60 Hz. The beat frequency is the difference, 66 − 60 = 6 per second. Adding or halving these does not give the beat count. Answer (4).

Q. Two sound waves with wavelengths 5.0 m and 5.5 m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second :

Explanation

Reviewed by Dr. Abubacker

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