Q. In a set of reactions propionic acid yielded a compound D. CH₃CH₂COOH —(SOCl₂)→ B —(NH₃)→ C —(KOH, Br₂)→ D The structure of D would be :
A) CH₃CH₂CH₂NH₂
B) CH₃CH₂CONH₂
C) CH₃CH₂NHCH₃
D) CH₃CH₂NH₂
Explanation
[Solution from source] SOCl₂ converts the acid to propanoyl chloride, CH₃CH₂COCl, and NH₃ then gives propanamide, CH₃CH₂CONH₂. Br₂/KOH carries out the Hofmann bromamide degradation, removing one carbon to give ethylamine, CH₃CH₂NH₂, as the final compound. Propylamine would keep all three carbons, and propanamide is only the intermediate before the Hofmann step. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.