The enthalpy and entropy change for the reaction : Br₂(l) + Cl₂(g) → 2BrCl(g) are 30 kJ mol⁻¹ and 105 J K⁻¹ mol⁻¹ respectively. The temperature at which the reaction will be in equilibrium is :

Question

Dr. Abubacker · Accepted Answer

[Solution from source] At equilibrium ΔG = ΔH − TΔS = 0, so T = ΔH/ΔS = 30 000 J mol⁻¹/105 J K⁻¹ mol⁻¹ = 285.7 K. Forgetting to convert kJ to J gives a meaningless 0.29 K. Answer (1).

Q. The enthalpy and entropy change for the reaction : Br₂(l) + Cl₂(g) → 2BrCl(g) are 30 kJ mol⁻¹ and 105 J K⁻¹ mol⁻¹ respectively. The temperature at which the reaction will be in equilibrium is :

Explanation

Reviewed by Dr. Abubacker

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