Q. The correct order regarding the electronegativity of hybrid orbitals of carbon is :

A) sp > sp² < sp³
B) sp > sp² > sp³
C) sp < sp² > sp³
D) sp < sp² < sp³
Explanation

[Solution from source] The more s-character in a hybrid orbital, the closer its electrons are held to the nucleus and the more electronegative it is. s-character is 50% in sp, 33% in sp² and 25% in sp³, so electronegativity is sp > sp² > sp³. This is why ethyne's C–H is the most acidic. Answer (2).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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