Q. A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is :
A) 2 Hz
B) 1.5 Hz
C) 0.5 Hz
D) 1 Hz
Explanation
[Solution from source] v_max = Aω, so ω = 31.4/5 = 6.28 rad/s and f = ω/2π = 1 Hz. Taking 6.28 as the frequency or dividing wrongly gives 2 Hz or 0.5 Hz. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.