Two boys are standing at the ends A and B of a ground, where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v₁. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is :

Question

Dr. Abubacker · Accepted Answer

[Solution from source] The catcher runs along the hypotenuse of a right triangle with legs a and v₁t: (vt)² = a² + (v₁t)², so t = √(a²/(v² − v₁²)). a/(v − v₁) would apply only if both ran along the same line. Answer (2).

Q. Two boys are standing at the ends A and B of a ground, where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v₁. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is :

Explanation

Reviewed by Dr. Abubacker

Want to attempt the full paper?