Q. Copper has face-centered cubic (fcc) lattice with interatomic spacing equal to 2.54 Å. The value of lattice constant for this lattice is :
A) 2.29 Å
B) 3.29 Å
C) 2.59 Å
D) 3.59 Å
Explanation
[Solution from source] In an fcc lattice atoms touch along the face diagonal, so the nearest-neighbour distance d = a/√2. a = √2 × 2.54 ≈ 3.59 Å. Taking a = d or dividing by √2 gives the smaller values. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.