Q. Aniline in a set of reactions yielded a product D. C₆H₅NH₂ —(NaNO₂/HCl)→ A —(CuCN)→ B —(H₂/Ni)→ C —(HNO₂)→ D The structure of the product D would be :
A) C₆H₅CH₂NH₂
B) C₆H₅NHCH₂CH₃
C) C₆H₅NHOH
D) C₆H₅CH₂OH
Explanation
[Solution from source] Aniline → benzenediazonium chloride → (CuCN) benzonitrile → (H₂/Ni) benzylamine C₆H₅CH₂NH₂ → (HNO₂) benzyl alcohol C₆H₅CH₂OH. Benzylamine is only intermediate C; nitrous acid converts this primary aliphatic amine to the alcohol. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.