Q. A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three α-particles in succession. The group of the periodic table to which the resulting daughter element would belong is :

A) Group 14
B) Group 16
C) Group 4
D) Group 6
Explanation

[Solution from source] Each α-emission lowers Z by 2, so three α-particles lower Z by 6, i.e. six places back in the periodic table. From group 2 this goes to group 14 of the previous period (e.g. Ra, Z = 88 → Pb, Z = 82). Answer (1).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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