Q. The rate of reaction between two reactants A and B decreases by a factor of 4, if the concentration of reactant B is doubled. The order of this reaction with respect to reactant B is :
A) -1
B) -2
C) 1
D) 2
Explanation
[Solution from source] rate ∝ [B]ⁿ. Doubling [B] makes the rate one quarter: 2ⁿ = 1/4, so n = −2. Order +2 would make the rate four times larger. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.