Q. At a particular locus, frequency of 'A' allele is 0.6 and that of 'a' is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium ?
A) 0.16
B) 0.48
C) 0.36
D) 0.24
Explanation
[Solution from source] By the Hardy-Weinberg principle, the heterozygote frequency is 2pq = 2 × 0.6 × 0.4 = 0.48. 0.36 (p²) and 0.16 (q²) are the frequencies of the two homozygotes. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.