A coin is tossed three times. Let $X$ denote the number of times a tail follows a head. If $\mu$ and $\sigma^2$ denote the mean and variance of $X$, then the value of $64(\mu+\sigma^2)$ is :

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] $X=1$ for HHT, HTH, HTT, THT and $X=0$ for the other four outcomes. So $\mu=\frac12$ and $\sigma^2=\frac12-\frac14=\frac14$, giving $64\cdot\frac34=48$. Answer (4).

Q. A coin is tossed three times. Let $X$ denote the number of times a tail follows a head. If $\mu$ and $\sigma^2$ denote the mean and variance of $X$, then the value of $64(\mu+\sigma^2)$ is :

Explanation

Reviewed by Dr. Abubacker

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