Q. If $B$ is magnetic field and $\mu_0$ is permeability of free space, then the dimensions of $(B/\mu_0)$ is
A) $ML^2T^{-2}A^{-1}$
B) $MT^{-2}A^{-1}$
C) $L^{-1}A$
D) $LT^{-2}A^{-1}$
Explanation
[Solution by Dr. Abubacker] $B=\mu_0nI$, so $\frac B{\mu_0}=nI$ has dimensions $L^{-1}A$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.