Two soap bubbles of radius 2 cm and 4 cm , respectively, are in contact with each other. The radius of curvature of the common surface, in cm , is _______ .

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] The excess pressure across the common surface is $4T\left(\frac1{r_1}-\frac1{r_2}ight)=\frac{4T}{r}$, so $r=\frac{r_1r_2}{r_2-r_1}=\frac{2	imes4}{2}=4$ cm. Answer: 4.

Q. Two soap bubbles of radius 2 cm and 4 cm , respectively, are in contact with each other. The radius of curvature of the common surface, in cm , is _______ .

Explanation

Reviewed by Dr. Abubacker

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