A vessel at 1000 K contains CO₂ with a pressure of 0.5 atm. Some of CO₂ is converted into CO on addition of graphite. If total pressure at equilibrium is 0.8 atm, then Kp is :

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] CO₂ + C ⇌ 2CO. If $x$ atm of CO₂ reacts, $P_{CO_2}=0.5-x$ and $P_{CO}=2x$, so the total is $0.5+x=0.8$ and $x=0.3$. Then $P_{CO_2}=0.2$ and $P_{CO}=0.6$, giving $K_p=\frac{0.6^2}{0.2}=1.8$ atm. Answer (1).

Q. A vessel at 1000 K contains CO₂ with a pressure of 0.5 atm. Some of CO₂ is converted into CO on addition of graphite. If total pressure at equilibrium is 0.8 atm, then Kp is :

Explanation

Reviewed by Dr. Abubacker

Want to attempt the full paper?