A solution of aluminium chloride is electrolysed for 30 minutes using a current of 2 A. The amount of the aluminium deposited at the cathode is [Given : molar mass of aluminium and chlorine are 27 g mol⁻¹ and 35.5 g mol⁻¹ respectively. Faraday constant = 96500 C mol⁻¹]

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] $Q=2	imes1800=3600$ C. Al³⁺ + 3e⁻ → Al, so $m=\frac{27	imes3600}{3	imes96500}=0.336$ g. (The question assumes Al is deposited, as the key does.) Answer (2).

Q. A solution of aluminium chloride is electrolysed for 30 minutes using a current of 2 A. The amount of the aluminium deposited at the cathode is [Given : molar mass of aluminium and chlorine are 27 g mol⁻¹ and 35.5 g mol⁻¹ respectively. Faraday constant = 96500 C mol⁻¹]

Explanation

Reviewed by Dr. Abubacker

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