This is a numerical-answer question. The correct answer is shown below.
[Solution by Dr. Abubacker] Nitrobenzene → aniline → benzenediazonium chloride → chlorobenzene (Sandmeyer) → biphenyl (Wurtz–Fittig with Na/ether). Biphenyl is C₁₂H₁₀: 12 × 12 + 10 = 154 g mol⁻¹. Answer: 154.