[Solution by Dr. Abubacker] $(\lambda\vec a+2\vec b)\cdot(3\vec a-\lambda\vec b)=3\lambda-\frac{\lambda^2}2+3-2\lambda=0\Rightarrow\lambda^2-2\lambda-6=0$, so $\lambda=1\pm\sqrt7\approx3.65,\,-1.65$. Neither lies in $[-1,3]$, so there are no such values. Answer (3).