This is a numerical-answer question. The correct answer is shown below.
[Solution by Dr. Abubacker] Reflexivity gives the diagonal and transitivity forces $(1,3)$. Only $(2,1),(3,2),(3,1)$ can still be added. Checking transitivity, the valid additions are $\varnothing$, $\{(2,1)\}$, $\{(3,2)\}$ and all three. The last one makes an equivalence relation (symmetric), so the non-symmetric ones number $3$. Answer: 3.