[Solution by Dr. Abubacker] Only the air–film reflection suffers a phase change of $\pi$ (the film–glass reflection does not, since $2.0>1.45$). For the two reflected rays, destructive interference (minimum reflection, hence maximum transmission) needs path difference $2nt=m\lambda$; the minimum non-zero thickness is $m=1$: $t=\frac{\lambda}{2n}=\frac{550}{4}=137.5$ nm. Answer (1).