A ball of mass 100 g is projected with velocity 20 m/s at $60^\circ$ with horizontal. The decrease in kinetic energy of the ball during the motion from point of projection to highest point is

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] Initial KE $=\frac12(0.1)(20)^2=20$ J. At the highest point only the horizontal component remains, $v=20\cos60^\circ=10$ m/s, so KE $=5$ J. Decrease $=20-5=15$ J. Answer (2).

Q. A ball of mass 100 g is projected with velocity 20 m/s at $60^\circ$ with horizontal. The decrease in kinetic energy of the ball during the motion from point of projection to highest point is

Explanation

Reviewed by Dr. Abubacker

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