[Solution by Dr. Abubacker] $g\propto\frac M{R^2}$: $g_p=\frac4{2^2}\,g=g$, so $T=2\pi\sqrt{l/g}$ is the same and (A) is true. The mass of a pendulum is indeed unchanged, so (R) is true, but the period does not depend on mass, so (R) does not explain (A). Answer (4).