[Solution by Dr. Abubacker] The Grignard reagent formed from RBr is hydrolysed to R–H, so R must have the 2-methylbutane carbon skeleton. Replacing H by Br at each type of carbon gives four distinct bromides: 1-bromo-2-methylbutane, 2-bromo-2-methylbutane, 2-bromo-3-methylbutane and 1-bromo-3-methylbutane. Answer (2).