Q. Match the Compounds (List - I) with the appropriate Catalyst/Reagents (List - II) for their reduction into corresponding amines. [table] List - I (Compounds) | List - II (Catalyst/Reagents) ; (A) R–CO–NH₂ (amide) | (I) NaOH (aqueous) ; (B) nitrobenzene (C₆H₅–NO₂) | (II) H₂/Ni ; (C) R–C≡N (nitrile) | (III) LiAlH₄, H₂O ; (D) N-alkylphthalimide (phthalimide–N–R) | (IV) Sn, HCl [/table] Choose the correct answer from the options given below :
A) (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
B) (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
C) (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
D) (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
Explanation
[Solution by Dr. Abubacker] Amide → amine with LiAlH₄ (A–III). Nitroarene → arylamine with Sn/HCl (B–IV). Nitrile → primary amine by catalytic hydrogenation, H₂/Ni (C–II). N-Alkylphthalimide → primary amine by alkaline hydrolysis (Gabriel synthesis) (D–I). Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.