Q. Arrange the following compounds in increasing order of their dipole moment : $\mathrm{HBr},\ \mathrm{H_2S},\ \mathrm{NF_3}$ and $\mathrm{CHCl_3}$
A) H₂S < HBr < NF₃ < CHCl₃
B) NF₃ < HBr < H₂S < CHCl₃
C) HBr < H₂S < NF₃ < CHCl₃
D) CHCl₃ < NF₃ < HBr < H₂S
Explanation
[Solution by Dr. Abubacker] Dipole moments (D): NF₃ ≈ 0.24 (the N–F bond dipoles oppose the lone-pair dipole), HBr ≈ 0.82, H₂S ≈ 0.97, CHCl₃ ≈ 1.04. So NF₃ < HBr < H₂S < CHCl₃. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.