Q. Niobium (Nb) and ruthenium (Ru) have "x" and "y" number of electrons in their respective 4d orbitals. The value of x + y is ______ -.
Numerical Question
This is a numerical-answer question. The correct answer is shown below.
Explanation
[Solution by Dr. Abubacker] Nb: [Kr] 4d⁴ 5s¹ (x = 4). Ru: [Kr] 4d⁷ 5s¹ (y = 7). x + y = 11. Answer: 11.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.