[Solution by Dr. Abubacker] Die 1 faces: 1,1,2,2,3,4; die 2 faces: 1,2,2,3,3,4 (36 equally likely outcomes). Sum $4$: (1,3)$\to2\cdot2=4$, (2,2)$\to2\cdot2=4$, (3,1)$\to1$: total 9. Sum $5$: (1,4)$\to2$, (2,3)$\to4$, (3,2)$\to2$, (4,1)$\to1$: total 9. Probability $=\frac{18}{36}=\frac12$. Answer (2).