This is a numerical-answer question. The correct answer is shown below.
[Solution by Dr. Abubacker] Let $f(x)=5x^3-15x$; $f'(x)=0$ at $x=\pm1$ with $f(-1)=10$ (local max) and $f(1)=-10$ (local min). Three distinct real roots exist when $-10<a<10$, so $\alpha=-10$, $\beta=10$ and $\beta-2\alpha=30$. Answer: 30.