The electric flux is $\phi=\alpha\sigma+\beta\lambda$ where $\lambda$ and $\sigma$ are linear and surface charge density, respectively. $\left(\frac\alpha\beta\right)$ represents

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] $[\alpha]=\frac{[\phi]}{[\sigma]}$ and $[\beta]=\frac{[\phi]}{[\lambda]}$, so $\frac\alpha\beta=\frac\lambda\sigma=\frac{C\,m^{-1}}{C\,m^{-2}}=m$, which has the dimension of length, i.e. a displacement. Answer (4).

Q. The electric flux is $\phi=\alpha\sigma+\beta\lambda$ where $\lambda$ and $\sigma$ are linear and surface charge density, respectively. $\left(\frac\alpha\beta\right)$ represents

Explanation

Reviewed by Dr. Abubacker

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