Q. A sub-atomic particle of mass $10^{-30}$ kg is moving with a velocity $2.21\times10^6$ m/s. Under the matter wave consideration, the particle will behave closely like ($h=6.63\times10^{-34}$ J.s)

A) Visible radiation
B) Gamma rays
C) Infra-red radiation
D) X-rays
Explanation

[Solution by Dr. Abubacker] $\lambda=\frac h{mv}=\frac{6.63\times10^{-34}}{10^{-30}\times2.21\times10^6}=3\times10^{-10}$ m $=3$ Å, which lies in the X-ray region. Answer (4).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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