Q.
A gun fires a lead bullet of temperature 300 K into a wooden block. The bullet having melting temperature of 600 K penetrates into the block and melts down. If the total heat required for the process is 625 J, then the mass of the bullet is ______ grams. (Latent heat of fusion of lead $=2.5\times10^4\,\mathrm{J\,kg^{-1}}$ and specific heat capacity of lead $=125\,\mathrm{J\,kg^{-1}K^{-1}}$)
A) 10
B) 20
C) 5
D) 15
Explanation
[Solution by Dr. Abubacker] $Q=m\left(c\Delta T+L\right)=m(125\times300+2.5\times10^4)=62500\,m=625\Rightarrow m=0.01$ kg $=10$ g. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.