Q. Propane molecule on chlorination under photochemical condition gives two di-chloro products, " x " and " y ". Amongst " x " and " y ", " x " is an optically active molecule. How many tri-chloro products (consider only structural isomers) will be obtained from " x " when it is further treated with chlorine under the photochemical condition?
A) 2
B) 5
C) 4
D) 3
Explanation
[Solution by Dr. Abubacker] The optically active dichloropropane is 1,2-dichloropropane, CH₃–CHCl–CH₂Cl (it has a chiral centre). Further chlorination can replace H on C-1 (1,1,2-), on C-2 (1,2,2-) or on C-3 (1,2,3-trichloropropane): 3 structural isomers. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.