[Solution by Dr. Abubacker] $\bar\nu=\frac1\lambda=\frac1{900\times10^{-7}\,\mathrm{cm}}=1.11\times10^4\ \mathrm{cm^{-1}}=\frac{R_H}9$. Since $R_H\left(\frac1{3^2}-\frac1{\infty^2}\right)=\frac{R_H}9$, this is the Paschen series limit, $\infty\to3$. Answer (3).