During " S " estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is ______ %. (Given molar mass in $\mathrm{g\,mol^{-1}}$ of Ba : 137, S : 32, O : 16 )

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] $\mathrm{BaSO_4}$ has molar mass $233$. Mass of S $=\frac{32}{233}	imes466=64$ mg. $\%\,\mathrm S=\frac{64}{160}	imes100=40$. Answer: 40.

Q. During " S " estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is ______ %. (Given molar mass in $\mathrm{g\,mol^{-1}}$ of Ba : 137, S : 32, O : 16 )

Explanation

Reviewed by Dr. Abubacker

Want to attempt the full paper?