Q. Let $A=\{(x,y)\in\mathbf R\times\mathbf R:|x+y|\ge3\}$ and $B=\{(x,y)\in\mathbf R\times\mathbf R:|x|+|y|\le3\}$. If $C=\{(x,y)\in A\cap B:x=0\text{ or }y=0\}$, then $\sum_{(x,y)\in C}|x+y|$ is :

A) 15
B) 24
C) 18
D) 12
Explanation

[Solution by Dr. Abubacker] On $x=0$: $|y|\ge3$ and $|y|\le3$ give $y=\pm3$. On $y=0$: $x=\pm3$. So $C=\{(0,\pm3),(\pm3,0)\}$ and each point has $|x+y|=3$. Sum $=12$. Answer (4).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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