A galvanometer having a coil of resistance $30\,\Omega$ need 20 mA of current for full-scale deflection. If a maximum current of 3 A is to be measured using this galvanometer, the resistance of the shunt to be added to the galvanometer should be $\frac{30}X\,\Omega$, where $X$ is

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] $S=\frac{I_gG}{I-I_g}=\frac{0.02	imes30}{3-0.02}=\frac{0.6}{2.98}=\frac{30}{149}\,\Omega$, so $X=149$. Answer (2).

Q. A galvanometer having a coil of resistance $30\,\Omega$ need 20 mA of current for full-scale deflection. If a maximum current of 3 A is to be measured using this galvanometer, the resistance of the shunt to be added to the galvanometer should be $\frac{30}X\,\Omega$, where $X$ is

Explanation

Reviewed by Dr. Abubacker

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