Q. A ball having kinetic energy KE, is projected at an angle of $60^\circ$ from the horizontal. What will be the kinetic energy of ball at the highest point of its flight ?
A) $\frac{(KE)}8$
B) $\frac{(KE)}2$
C) $\frac{(KE)}{16}$
D) $\frac{(KE)}4$
Explanation
[Solution by Dr. Abubacker] At the top only the horizontal velocity $v\cos60^\circ=\frac v2$ remains, so the KE is $\frac{KE}{4}$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.