Two charges $7\,\mu c$ and $-4\,\mu c$ are placed at $(-7\ \mathrm{cm},0,0)$ and $(7\ \mathrm{cm},0,0)$ respectively. Given, $\epsilon_0=8.85 imes10^{-12}\ \mathrm{C^2N^{-1}m^{-2}}$, the electrostatic potential energy of the charge configuration is :

Question

Two charges $7\,\mu c$ and $-4\,\mu c$ are placed at $(-7\ \mathrm{cm},0,0)$ and $(7\ \mathrm{cm},0,0)$ respectively. Given, $\epsilon_0=8.85	imes10^{-12}\ \mathrm{C^2N^{-1}m^{-2}}$, the electrostatic potential energy of the charge configuration is :

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] The separation is $14$ cm. $U=\frac{q_1q_2}{4\pi\epsilon_0r}=\frac{9	imes10^9	imes7	imes10^{-6}	imes(-4	imes10^{-6})}{0.14}=-1.8$ J. Answer (1).

Q. Two charges $7\,\mu c$ and $-4\,\mu c$ are placed at $(-7\ \mathrm{cm},0,0)$ and $(7\ \mathrm{cm},0,0)$ respectively. Given, $\epsilon_0=8.85\times10^{-12}\ \mathrm{C^2N^{-1}m^{-2}}$, the electrostatic potential energy of the charge configuration is :

Explanation

Reviewed by Dr. Abubacker

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