Q.
Two point charges $-4\,\mu c$ and $4\,\mu c$, constituting an electric dipole, are placed at $(-9,0,0)$cm and $(9,0,0)$cm in a uniform electric field of strength $10^4\,\mathrm{NC^{-1}}$. The work done on the dipole in rotating it from the equilibrium through $180^\circ$ is :
A) 18.4 mJ
B) 14.4 mJ
C) 12.4 mJ
D) 16.4 mJ
Explanation
[Solution by Dr. Abubacker] $p=qd=4\times10^{-6}\times0.18=7.2\times10^{-7}$ C m. Work to rotate by $180^\circ$ from equilibrium: $W=2pE=2\times7.2\times10^{-7}\times10^4=14.4\times10^{-3}$ J $=14.4$ mJ. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.