Q. The equation of a transverse wave travelling along a string is $y(x,t)=4.0\sin\left[20\times10^{-3}x+600t\right]$ mm, where $x$ is in mm and $t$ is in second. The velocity of the wave is :

A) $-60$ m/s
B) $-30$ m/s
C) $+30$ m/s
D) $+60$ m/s
Explanation

[Solution by Dr. Abubacker] $k=20\times10^{-3}\ \mathrm{mm^{-1}}$, $\omega=600\ \mathrm{s^{-1}}$. $|v|=\frac\omega k=3\times10^4$ mm/s $=30$ m/s. The $+$ sign between $kx$ and $\omega t$ means the wave travels in the $-x$ direction: $v=-30$ m/s. Answer (2).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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