[Solution by Dr. Abubacker] $k=20\times10^{-3}\ \mathrm{mm^{-1}}$, $\omega=600\ \mathrm{s^{-1}}$. $|v|=\frac\omega k=3\times10^4$ mm/s $=30$ m/s. The $+$ sign between $kx$ and $\omega t$ means the wave travels in the $-x$ direction: $v=-30$ m/s. Answer (2).