This is a numerical-answer question. The correct answer is shown below.
[Solution by Dr. Abubacker] Two C=C bonds (2 mol H₂). Reassembling the three oxidation fragments (acetone, acetic acid and 4-oxopentanoic acid) across the two cleaved C=C bonds gives X = CH₃CH=C(CH₃)–CH₂CH₂–CH=C(CH₃)₂, C₁₀H₁₈. σ bonds: 18 C–H + 9 C–C (the acyclic skeleton of 10 carbons; each C=C contributes one σ and one π) = 27. Answer: 27.