When 81.0 g of aluminium is allowed to react with 128.0 g of oxygen gas, the mass of aluminium oxide produced in grams is ______ - (Nearest integer) Given : Molar mass of Al is $27.0\ \mathrm{g\,mol^{-1}}$ Molar mass of O is $16.0\ \mathrm{g\,mol^{-1}}$

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] $4\,\mathrm{Al}+3\,\mathrm{O_2}	o2\,\mathrm{Al_2O_3}$. Al: $\frac{81}{27}=3$ mol; O₂: $\frac{128}{32}=4$ mol. $3$ mol Al needs only $2.25$ mol O₂, so Al is limiting and gives $1.5$ mol of Al₂O₃ (102 g/mol): $1.5	imes102=153$ g. Answer: 153.

Q. When 81.0 g of aluminium is allowed to react with 128.0 g of oxygen gas, the mass of aluminium oxide produced in grams is ______ - (Nearest integer) Given : Molar mass of Al is $27.0\ \mathrm{g\,mol^{-1}}$ Molar mass of O is $16.0\ \mathrm{g\,mol^{-1}}$

Explanation

Reviewed by Dr. Abubacker

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