A current of $5$A exists in a square loop of side $\frac1{\sqrt2}$ m. Then the magnitude of the magnetic field $B$ at the centre of the square loop will be $p imes10^{-6}$ T. where, value of p is ______. [Take $\mu_0=4\pi imes10^{-7}\, ext{TmA}^{-1}$].

Question

A current of $5$A exists in a square loop of side $\frac1{\sqrt2}$ m. Then the magnitude of the magnetic field $B$ at the centre of the square loop will be $p	imes10^{-6}$ T. where, value of p is ______. [Take $\mu_0=4\pi	imes10^{-7}\,	ext{TmA}^{-1}$].

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] For a square loop of side $a$: $B=\frac{2\sqrt2\mu_0I}{\pi a}=\frac{2\sqrt2\cdot4\pi	imes10^{-7}\cdot5}{\pi\cdot\frac1{\sqrt2}}=2\sqrt2\cdot\sqrt2\cdot20	imes10^{-7}=8	imes10^{-6}$ T. So $p=8$. Answer: 8.

Q. A current of $5$A exists in a square loop of side $\frac1{\sqrt2}$ m. Then the magnitude of the magnetic field $B$ at the centre of the square loop will be $p\times10^{-6}$ T. where, value of p is ______. [Take $\mu_0=4\pi\times10^{-7}\,\text{TmA}^{-1}$].

Explanation

Reviewed by Dr. Abubacker

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