A wire of resistance $9\Omega$ is bent to form an equilateral triangle. Then the equivalent resistance across any two vertices will be ______ ohm.

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] Each side has $3\,\Omega$. Between two vertices, one side ($3\,\Omega$) is in parallel with the other two in series ($6\,\Omega$): $\frac{3\cdot6}{3+6}=2\,\Omega$. Answer: 2.

Q. A wire of resistance $9\Omega$ is bent to form an equilateral triangle. Then the equivalent resistance across any two vertices will be ______ ohm.

Explanation

Reviewed by Dr. Abubacker

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