Q. For a reaction, $\text{N}_2\text{O}_{5(g)}\to2\text{NO}_{2(g)}+\frac12\text{O}_{2(g)}$ in a constant volume container, no products were present initially. The final pressure of the system when $50\%$ of reaction gets completed is
A) 5 times of initial pressure
B) 5/2 times of initial pressure
C) 7/2 times of initial pressure
D) 7/4 times of initial pressure
Explanation
[Solution by Dr. Abubacker] Let the initial pressure be $P_0$. At $50\%$ completion: $\text{N}_2\text{O}_5=0.5P_0$, $\text{NO}_2=1.0P_0$, $\text{O}_2=0.25P_0$. Total $=1.75P_0=\frac74P_0$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.