Q. One mole of the octahedral complex compound $\text{Co(NH}_3)_5\text{Cl}_3$ gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with excess of $\text{AgNO}_3$ solution to yield two moles of $\text{AgCl}_{(s)}$. The structure of the complex is:

A) $[\text{Co(NH}_3)_4\text{Cl}_2]\cdot\text{Cl}\cdot\text{NH}_3$
B) $[\text{Co(NH}_3)_3\text{Cl}_3]\cdot2\text{NH}_3$
C) $[\text{Co(NH}_3)_5\text{Cl}]\text{Cl}_2$
D) $[\text{Co(NH}_3)_4\text{Cl}]\cdot\text{Cl}_2\cdot\text{NH}_3$
Explanation

[Solution by Dr. Abubacker] Three ions means one complex cation and two counter ions; two moles of AgCl means two ionisable chlorides. So the formula is $[\text{Co(NH}_3)_5\text{Cl}]\text{Cl}_2$ (octahedral, 6 ligands). Answer (3).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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