Q. Which of the following statement is true with respect to $\text{H}_2\text{O},\text{NH}_3$ and $\text{CH}_4$? A. The central atoms of all the molecules are $sp^3$ hybridized. B. The $\text{H-O-H},\text{H-N-H}$ and $\text{H-C-H}$ angles in the above molecules are $104.5^\circ,107.5^\circ$ and $109.5^\circ$, respectively. C. The increasing order of dipole moment is $\text{CH}_4<\text{NH}_3<\text{H}_2\text{O}$. D. Both $\text{H}_2\text{O}$ and $\text{NH}_3$ are Lewis acids and $\text{CH}_4$ is a Lewis base. E. A solution of $\text{NH}_3$ in $\text{H}_2\text{O}$ is basic. In this solution $\text{NH}_3$ and $\text{H}_2\text{O}$ act as Lowry-Bronsted acid and base respectively. Choose the correct answer from the options given below:
A) A, B and C Only
B) A, D and E Only
C) C, D and E Only
D) A, B, C and E Only
Explanation
[Solution by Dr. Abubacker] A, B and C are correct ($\mu$: $\text{CH}_4=0<\text{NH}_3<\text{H}_2\text{O}$). D is false ($\text{H}_2\text{O}$ and $\text{NH}_3$ are Lewis bases, $\text{CH}_4$ is neither). E is false: in the solution $\text{NH}_3$ acts as the Bronsted base and $\text{H}_2\text{O}$ as the acid. So A, B and C only. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.